Posted by Naz on Sunday, November 7, 2010 at 12:38pm.
To find the derivative, you must use the product rule
f'(x) = u'*v + u*v'
So,
f(x) = x^2*(2x+1)^3
f'(x)=(2x)(2x+1)^3+(x^2)(3)(2x+1)^2(2)
(need chain rule, too)
Simplify
(2x)(2x+1)^2(5x+1)
(10x^2+2x)(2x+1)^2
In the form
y-y1 = m(x-x1)
y+1 = (10x^2+2x)(2x+1)^2(x+1)
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