Posted by **Scott** on Sunday, November 7, 2010 at 12:41am.

The angular position of a point on the rim of a rotating wheel is given by Theta = 4.0t-3t^2+t^3, where theta is in radians and t is in seconds. At t=0, what are (a.) the point's angular position and (b.) its angular velocity? (c.) What is its angular velocity at t=4.0s? What are the instantaneous angular accelerations at (d.) the beginning and (e.) the end of this time interval?

## Answer This Question

## Related Questions

- Physics - The angular position of a point on the rim of a rotating wheel is ...
- physics - The angle through which a rotating wheel has turned in time t is given...
- physics - The angular position of a point on the rim of a rotating wheel is ...
- physics - The angle through which a rotating wheel has turned in time t is given...
- physics - The angular position of a point on the rim of a 45.8 cm rotating wheel...
- Calculus (fixed the typo ) - A line rotates in a horizontal plane according to ...
- Calculus PLEASE check my work , - 1.) which of the following represents dy/dx ...
- Calculus 12th grade (double check my work please) - 1.) which of the following ...
- Physics - The angular position of a point on the rim of a rotating wheel is ...
- Physics - angular acceleration - An object rotates about a fixed axis, and th ...

More Related Questions