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April 1, 2015

April 1, 2015

Posted by **Anonymous** on Saturday, November 6, 2010 at 10:50pm.

- chemistry -
**DrBob222**, Sunday, November 7, 2010 at 12:16amUse PV = nRT, substitute the numbers, and calculate mols CO2 initially, redo the formula and recalculate with new numbers to determine the moles CO2 remaining. The difference equals moles CO2 reacted.

Then let X = mass BaO

Let Y = mass CaO.

========================

X + Y = 5.31

(X/molar mass BaO) + (Y/molar mass CaO) = moles CO2 consumed (from above.)

Solve the two simultaneous equations for X and Y,

Then %BaO = (mass BaO/5.31)*100 = ??

%CaO = (mass CaO/5.31)*100 = ??

Post your work if you get stuck.

- chemistry -
**Anonymous**, Sunday, November 7, 2010 at 12:59ami have a hard time understanding how to calculate the moles of CO2 remaining?

how do you use the PV=nRT for the remaining CO2?

- chemistry -
**DrBob222**, Sunday, November 7, 2010 at 1:12amThe problem states that after the CO2 has reacted with BaO and CaO, the remaining pressure is 230 torr. So plug that back into PV = nRT for P, along with the other numbers, and calculate a new n. Subtracting the two will give you the amount that reacted.

- chemistry -
**Anonymous**, Sunday, November 7, 2010 at 1:23amfor T, do I have to convert C to Kelvin? would they yield the same answers?

- chemistry -
**Anonymous**, Sunday, November 7, 2010 at 1:33amX + Y = 5.31

(X/molar mass BaO) + (Y/molar mass CaO) = moles CO2 consumed (from above.)

Solve the two simultaneous equations for X and Y,

^I dont really understand this part either.

- chemistry -
**Anonymous**, Monday, October 24, 2011 at 7:52pmwhy is moles of CO2 consumed equal to the combined moles of BaO and CaO?

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