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September 30, 2014

September 30, 2014

Posted by **Naz** on Saturday, November 6, 2010 at 9:03pm.

[kite] <---15 ft/sec

. .

. .

. .

. .

. .

. .

320 ft .

. .

. .

. .

._____________.[girl]

So I listed my given data:

a=320 ft

b=240 ft

c=400 ft

And I know I have to find dc/dt when c=400 ft - using the Pythagorean theorem. I differentiated it but now I realize that I don't have da/dt and db/dt...what do I do?

- AP CALCULUS -
**Reiny**, Saturday, November 6, 2010 at 9:50pmI can see from your data that you labeled your triangle with a, b, and c

a being the vertical (fixed at 320) , b the horizontal and c the hypotenuse (the string)

so c^2 = b^2 + 320^2

you also found correctly that if c= 400, b = 240

differentiate ...

2c dc/dt = 2b db/dt + 0

dc/dt = b db/dt/c

= 240(15)/400 = 9

check my arithmetic

- AP CALCULUS -
**Reiny**, Saturday, November 6, 2010 at 9:51pmI was going to mention, that since a is a constant, da/dt = 0 as seen above.

- AP CALCULUS -
**Naz**, Saturday, November 6, 2010 at 10:08pmOhh thank you-that is what I had overlooked: the fact that the derivative of a constant is = to 0 and that is why I did not need da/dt. Thank You I understand where I went wrong now.

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