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November 25, 2014

November 25, 2014

Posted by **Nel** on Saturday, November 6, 2010 at 8:02pm.

(a) How fast is distance between the two bicyclists changing at this moment?

- AP CALC -
**Reiny**, Saturday, November 6, 2010 at 8:22pmmake a diagram, let the distance the north biker is from the intersection be y miles, let the distance the west biker is from the intersection be x miles

Let the distance between them be D

D^2 = x^2 + y^2

2D dD/dt = 2x dx/dt + 2y dy/dt

given:

dx/dt = 12 mph

dy/dt = -16 mph (y is decreasing)

find dD/dt when x=10 and y=8

then D^2 = 100+64

D = √164

dD/dt =(2(10)(12) + 2(8)(-16))/(2√164) = .....

you finish the arithmetic

- AP CALC -
**Nel**, Saturday, November 6, 2010 at 8:55pmMy final answer was -8/square root of 164. Is that correct?

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