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April 18, 2014

April 18, 2014

Posted by **Sal** on Saturday, November 6, 2010 at 3:49pm.

% of its normal value

- Physics -
**Damon**, Saturday, November 6, 2010 at 4:14pmflow rate Q2 =

v2 pi r2^2 = .3 v1 pi r1^2

v2/v1 = .3 (r1/r2)^2

.5 rho v2^2 =P2=1.4 P1=1.4*.5 rho v1^2

v2^2/v1^2 = 1.4

so

v2/v1 = 1.18

so

1.18 = .3(r1/r2)^2

r1/r2 = sqrt (1.18/.3)

= 2

so reduced to half the original radius

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