Posted by applebottom on Friday, November 5, 2010 at 8:05pm.
let z = tan x
z^2 +.8 z -3.84 = 0
z = [ -.8 +/- sqrt (.64 +15.36)]/2
z = [ -.8 +/- sqrt (16) ] / 2
z = [ -.8 +/- 4 ]/2
z = tan x = -2.4 or -1.6
tan is negative in quadrants 2 and 4
so
about -1 radian or about -1.18 radian
which is 2 pi - 1 and 2 pi - 1.18
also pi -1 and pi - 1.18
Related Questions
Trig - Find all solutions of the equation on the interval [0,2pi): Tan^2x=1-secx
Trig - can I please have help with these 3 questions? 1. Solve this equation ...
trig - please help me with some questions I skipped on a review for our test ...
Math - Solve the equation for x in the interval 0<x<2pi 1/ 1+tan^...
trig - solve the equation 2 tan C-3=3 tan X-4 algebraically for all values of C ...
PreCalculus - Hi I need some assistance on this problem find the exact value do ...
Solving Trig equation - Solve the trig equation exactly in the interval 0&#...
advanced functions - solve the first equation in each pair of equations or y and...
trig - Solve the equation 2 tan C - 3 = 3 tan C-4 algebraically for all values ...
Trig - Given: cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 &...
For Further Reading