Posted by Melissa on Friday, November 5, 2010 at 7:52pm.
Lets look at the math.
Sum of heats gained is zero.
50*Cmetal(Tf-100)+200*Cliquid(Tf-25)=0
Tf(50Cmetal+200Cliquid)=200Cliquid*25+5000Cmetal
Tf=(200Cliquid+5000Cmetal)/(50Cmetal+200Cliquid)
multiplying the right side numerator and deoominator by 1/cliquid
Tf=(200+5000cm/cl)/(50cm/cl+200)
let cm/cl be x.
well, it is apparent to me that the cm/cl term in the numerator predominates, so it needs to be maximized .
So the metal with the largest specific heat, and the liquid with the least.
so on the four choices, compute cm/cl . the winner is the highest ratio.
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