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October 26, 2014

October 26, 2014

Posted by **aok** on Friday, November 5, 2010 at 7:40pm.

(a) If its initial angular speed was 5.41 rad/s and it rotated 13.7 revolutions before coming to rest, what was its average angular acceleration?

- physics -
**bobpursley**, Friday, November 5, 2010 at 8:46pmwf^2=wi^2+2*alpha*displacement

where displacement = 13.7*2PI radians

wi=5.41 rad/sec, wf=0

solve for angular acceleration, in rad/s^2

- physics -
**Damon**, Friday, November 5, 2010 at 8:50pm13.7 * 2 pi = 86.08 radians total

average speed = 2.705 rad/s

so time to stop = 86.08/2.705 = 32.8 seconds

d = Vi t +(1/2) a t^2

86.08 = 5.41 (32.8) +.5 a (32.8)^2

86.08 = 172 + 538 a

-86 = 538 a

a = - 0.16 rad/s^2

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