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Posted by on Friday, November 5, 2010 at 7:40pm.

After fixing a flat tire on a bicycle you give the wheel a spin.
(a) If its initial angular speed was 5.41 rad/s and it rotated 13.7 revolutions before coming to rest, what was its average angular acceleration?

  • physics - , Friday, November 5, 2010 at 8:46pm

    wf^2=wi^2+2*alpha*displacement

    where displacement = 13.7*2PI radians
    wi=5.41 rad/sec, wf=0
    solve for angular acceleration, in rad/s^2

  • physics - , Friday, November 5, 2010 at 8:50pm

    13.7 * 2 pi = 86.08 radians total

    average speed = 2.705 rad/s
    so time to stop = 86.08/2.705 = 32.8 seconds

    d = Vi t +(1/2) a t^2

    86.08 = 5.41 (32.8) +.5 a (32.8)^2

    86.08 = 172 + 538 a

    -86 = 538 a

    a = - 0.16 rad/s^2

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