Posted by carly on Friday, November 5, 2010 at 7:03pm.
Kb = (Kw/Ka) = (OH^-)(C6H5COOH)/(C6H5COO^-)
Plug in values for Kw, Ka, x for OH and x for C6H5COOH, and 5.78E-3 for C6H5COO^-) and solve for x.
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