Posted by **Jessica 2** on Friday, November 5, 2010 at 6:19pm.

I have worked this problem out and just need confirmation. 15 + 2x - 5 = 130;

2x + 10 - 10 = 130 -10;

2x/2x = 120/2x;

x = 60.

- ALGEBRA -
**Jessica 2**, Friday, November 5, 2010 at 6:26pm
SO SORRY. PLEASE DISREGARD THE FIRST PROBLEM. I DID NOT POST THE ORIGINAL MATH PROBLEM. THIS IS THE ORIGINAL MATH PROBLEM 5 (3+4X) -5 = 130; 15+20x -5 =130;

20x +10 = 130;

20x +10-10 = 130 -10

20x/20x = 120/20x

x = 6

Thank you

- ALGEBRA -
**Quidditch**, Friday, November 5, 2010 at 8:15pm
6 is correct. However, your last step is not quite correct.

starting with...

20x + 10 - 10 = 130 - 10

20x = 120

Now divide both sides by 20, not 20x

20x/20 = 120/20

x = 6

- ALGEBRA -
**Jessica 2**, Friday, November 5, 2010 at 9:11pm
Thank you! I had thought something was wrong with the last step but could not figure it out. You were a great help!

- ALGEBRA -
**Quidditch**, Friday, November 5, 2010 at 9:29pm
You're welcome.

Glad to help

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