Posted by Nikki on Friday, November 5, 2010 at 5:51pm.
A street light is at the top of a 15 ft tall pole. A woman 6 ft tall walks away from the pole with a speed of 4 ft/sec along a straight path. How fast is the tip of her shadow moving when she is 30 ft from the base of the pole

calculus  Anonymous, Thursday, January 20, 2011 at 11:00am
hi nikki
As the man goes farther from the street light, his shadow grows.
You can see if drow the diagram , that you have two similar right triangles
So, y/(yx) = 15/6 and you can solve for y: y=5x/3.
Now differentiate both sides of this equation with respect to time t, then substitute in what you know for the values of the variables which are dx/dt ,y . Since you want the speed of the shadow, you want to find out what dy/dt equals.
Cheers,
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