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July 30, 2014

July 30, 2014

Posted by **Nikki** on Friday, November 5, 2010 at 5:51pm.

- calculus -
**Anonymous**, Thursday, January 20, 2011 at 11:00amhi nikki

As the man goes farther from the street light, his shadow grows.

You can see if drow the diagram , that you have two similar right triangles

So, y/(y-x) = 15/6 and you can solve for y: y=5x/3.

Now differentiate both sides of this equation with respect to time t, then substitute in what you know for the values of the variables which are dx/dt ,y . Since you want the speed of the shadow, you want to find out what dy/dt equals.

Cheers,

- calculus -
**mohammadhassan**, Thursday, January 20, 2011 at 11:00amhi nikki

As the man goes farther from the street light, his shadow grows.

You can see if drow the diagram , that you have two similar right triangles

So, y/(y-x) = 15/6 and you can solve for y: y=5x/3.

Now differentiate both sides of this equation with respect to time t, then substitute in what you know for the values of the variables which are dx/dt ,y . Since you want the speed of the shadow, you want to find out what dy/dt equals.

Cheers,

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