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August 20, 2014

Homework Help: college chemistry

Posted by sparkle on Friday, November 5, 2010 at 4:10am.

A solution of C6H5CO2Na hydrolyzes according to the equation. If the [C6H5CO2H] in the solution after hydrolysis is 0.00000294 M, calculate the equilibrium concentration of C6H5CO2Na.

C6H5CO2-(aq) + H2O(l) = OH-(aq) + C6H5CO2H(aq)

Kh=1.5910-10

What does Kh stand for? Is it the same as Kw?

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