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December 21, 2014

December 21, 2014

Posted by **chris** on Thursday, November 4, 2010 at 10:26pm.

- math -
**Reiny**, Thursday, November 4, 2010 at 10:45pmlet the number of $1 decreases be n

number sold = 1000 + 10n

price of each = 500 - n

profit = (1000 + 10n)(500-n) - 300(1000+10n) - 100000

expand this mess, differentiate it , then set that equal to zero

- inter alegbra -
**linda**, Sunday, November 14, 2010 at 12:37am$102.00

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