(10/((n^2)-1)+((2n-5)/(n-1))=(2n+5)/(n+1)
notice that n^2-1 = n(n+1)(n-1)
so the LCD is n^2-1
multiply by the LCD
10 + (2n-5)(n+1) = (2n+5)(n-1)
10 + 2n^2 -3n - 5 = 2n^2 +3n - 5
10 = 6n
n = 5/3
so the LCD is n^2-1
multiply by the LCD
10 + (2n-5)(n+1) = (2n+5)(n-1)
10 + 2n^2 -3n - 5 = 2n^2 +3n - 5
10 = 6n
n = 5/3