2.0g bullet fired with speed of 44.5m/s what is the kinetic? is there any conversions involved?
you have to change 2 grams to .002kg
KE= 1/2 m v^2, and it will work out in Joules if m is in kg, v is in m/s
THANK YOU! GOT IT
To find the kinetic energy of the bullet, we can use the formula:
Kinetic Energy = (1/2) * mass * velocity^2
In this case, the mass of the bullet is 2.0g, and the velocity is 44.5m/s.
Before we proceed with the calculation, we need to make sure that the units are consistent. The given mass is in grams (g), while the velocity is in meters per second (m/s). It's important to note that the units need to be in the same system, so we should convert the mass to kilograms (kg) for accurate calculations.
1 kilogram (kg) = 1000 grams (g)
Converting 2.0 grams to kilograms:
2.0g * (1 kg / 1000g) = 0.002 kg
Now, we can substitute the values into the kinetic energy formula:
Kinetic Energy = (1/2) * 0.002 kg * (44.5 m/s)^2
Simplifying the equation:
Kinetic Energy = (1/2) * 0.002 kg * (1980.25 m^2/s^2)
Kinetic Energy = 0.99 J (rounded to two decimal places)
Hence, the kinetic energy of the bullet is approximately 0.99 Joules.