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October 30, 2014

October 30, 2014

Posted by **Bella** on Thursday, November 4, 2010 at 8:32pm.

- Physics -
**bobpursley**, Thursday, November 4, 2010 at 8:45pmwell, tension is 2.57g up the slide

static friction is .605*M1*g*cosTheta, down the slide

gravity down the slide=M1*g*sinTheta

so,

2.57g=.605M1*g*cosTheta-M1*g*sinTheta

solve for M1

check my thinking and typing.

- Physics -
**Scotty**, Tuesday, February 15, 2011 at 7:10pmBob was mostly right, however when he took into consideration of the gravity on the down side he forgot to input the static friction that goes against gravity pulling the block down the slope.

Tension= (Us*(mass*9.8cos(theta))-((mass*9.8sin(20))-(Us*(mass*9.8cos(20))

So without numbers and only variables:

T=(Us*N)-(g)-(Us*N)

obviously, when you have a slope, you have to factor the theta in, as I did in the first equation.

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