Post a New Question


posted by .

A rotating wheel requires 9.00 s to rotate 29.0 revolutions. Its angular velocity at the end of the 9.00 s interval is 98.0 rad/s. What is the constant angular acceleration of the wheel in radians/second squared? (Do not assume that the wheel starts at rest.)

  • Physics -

    displacement=Wi*t+1/2 alpha*t^2

    where alpha is the angular acceleration in rev/sec

    you know:
    29=wi*9+1/2 alpha*81

    and you know
    wf=98/2PI rev/sec=wi+alpha*9

    wi= 98/2PI-alpha*9
    putting that in to the first equation
    29=(98/2PI-alpha*9)*9 +1/2 alpha*81
    solve for alpha. Now this alpha will be in rev/s^2, in radians/sec^2, divide rev by 2PI to get that.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question