Posted by **Annie** on Thursday, November 4, 2010 at 8:21pm.

A rotating wheel requires 9.00 s to rotate 29.0 revolutions. Its angular velocity at the end of the 9.00 s interval is 98.0 rad/s. What is the constant angular acceleration of the wheel in radians/second squared? (Do not assume that the wheel starts at rest.)

- Physics -
**bobpursley**, Thursday, November 4, 2010 at 8:50pm
displacement=Wi*t+1/2 alpha*t^2

where alpha is the angular acceleration in rev/sec

you know:

29=wi*9+1/2 alpha*81

and you know

wf=98/2PI rev/sec=wi+alpha*9

wi= 98/2PI-alpha*9

putting that in to the first equation

29=(98/2PI-alpha*9)*9 +1/2 alpha*81

solve for alpha. Now this alpha will be in rev/s^2, in radians/sec^2, divide rev by 2PI to get that.

## Answer This Question

## Related Questions

- Physics - A rotating wheel requires 8.00 s to rotate 29.0 revolutions. Its ...
- physics - A rotating wheel requires 6.00 s to rotate 27.0 revolutions. Its ...
- physics - A rotating wheel requires 5.00 s to rotate 30.0 revolutions. Its ...
- science- physics - A rotating wheel requires 4.17 s to rotate through 37 rev. ...
- Physics - Starting from rest at t = 0 s, a wheel undergoes a constant angular ...
- physics - Starting from rest at t = 0 s, a wheel undergoes a constant angular ...
- physics - Starting from rest at t = 0 s, a wheel undergoes a constant angular ...
- Physics - A spinning wheel is slowed down by a brake, giving it a constant ...
- Physics 1 (Calc Based) - At t = 0, a wheel rotating about a fixed axis at a ...
- Physics - The angular position of a point on the rim of a rotating wheel is ...

More Related Questions