Posted by **Sam** on Thursday, November 4, 2010 at 8:18pm.

A dentist's drill starts from rest. After 3.20 s of constant angular acceleration it turns at a rate of 2.7 104 rev/min.

(a) Find the drill's angular acceleration.

(b) Determine the angle (in radians) through which the drill rotates during this period.

- Physics -
**Henry**, Saturday, November 6, 2010 at 1:02am
V = 2.7104 rev / min.

V = 2.7104 rev/min * 1 / 60 min/s = 0.04517 rev/s.

a. a = 0.04517 rev/s / 3.2 s =

0.01412 rev/s^2.

b. A = 0.04517 rev/s * 3.2 s * 6.28 rad/rev = 0.91 Radians.

- Physics -
**yeah**, Sunday, October 2, 2011 at 7:16am
i've a question, where did u get 6.28 rad/rev?

- Physics -
**Anonymous**, Thursday, November 3, 2011 at 12:31am
2pie equals 6.28

- Physics -
**Tina**, Monday, November 12, 2012 at 12:12pm
I have a question. 2.7104 was that suppose to actually be 2.7*10^4?

- Physics -
**tonnie**, Monday, March 2, 2015 at 10:16am
A dentist's drill starts from rest it truns at a rate of 2.22*10^5 rpm at 3.5s.

1)find the angular acceleration of the drill.

2)through how many revolution the drill rotates during this period.

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