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March 7, 2015

Posted by **Joey** on Thursday, November 4, 2010 at 7:36pm.

Please help

Physics-Please help - bobpursley, Thursday, November 4, 2010 at 5:52pm

THe PE is .9 where? Where did the coaster start?

Physics-Please help - Joey, Thursday, November 4, 2010 at 5:54pm

The coaster started at .18PE-the .9 is the PE at the top of the second hill.The second hill is lower.

Physics-Please help - bobpursley, Thursday, November 4, 2010 at 6:01pm

Well, the difference in the two Potential energies is now KEnergy, 1/2 mv^2, solve for v.

Physics-Please check - Joey, Thursday, November 4, 2010 at 6:21pm

. The way to calculate this is you take the KE would be .9. You would say .9 = ½ (.035 x v^2) = 2.215. Correct or no?

Physics-Please check - Joey, Thursday, November 4, 2010 at 7:31pm

Should I have done this as 1/2mv^2 = mgh

Cross out like terms and get to v^2 = square root of 2 x g x .25m(h)= 2.125 m/s

Would this be correct?

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