Thursday
March 23, 2017

Post a New Question

Posted by on Thursday, November 4, 2010 at 7:33pm.

Consider the equation 3x+5y=k, what values could k so that the x-intercept and y- intercept on the equations graph would both be integers. explain.

  • 8th grade - , Friday, November 5, 2010 at 3:04am

    If this is algebra, for example, please label the School Subject correctly. Otherwise the correct teacher may never read your post.

    Sra

  • 8th grade - , Friday, November 5, 2010 at 11:57pm

    3X + 5Y = K.

    k = A * B = 3 * 5 = 15.
    3 and 5 are now factors of 15.
    Therefore, 15 is divisible by both:

    3X + 5Y = 15,
    Let X = 0,
    3*0 + 5Y = 15,
    5Y = 15,
    Y = 3 = Y-Int.

    Let Y = 0,
    3X + 5*0 = 15,
    3X = 15,
    X = 5 = X-Int.

    Graph: (0 , 3) , (5 , 0).

  • 8th grade - , Thursday, September 19, 2013 at 5:00pm

    15!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!LOL IDK

  • 8th grade - , Thursday, September 3, 2015 at 2:18pm

    It is 15=k math is fun and awesome!!!

  • 8th grade - , Thursday, September 3, 2015 at 2:28pm

    15 is the answer and I have a question "if a is not equal to 0, find the intercepts of the graph of y=ax+b in terms of a and b?"

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question