Posted by Monkeylover:) on Thursday, November 4, 2010 at 7:33pm.
Consider the equation 3x+5y=k, what values could k so that the xintercept and y intercept on the equations graph would both be integers. explain.

8th grade  SraJMcGin, Friday, November 5, 2010 at 3:04am
If this is algebra, for example, please label the School Subject correctly. Otherwise the correct teacher may never read your post.
Sra 
8th grade  Henry, Friday, November 5, 2010 at 11:57pm
3X + 5Y = K.
k = A * B = 3 * 5 = 15.
3 and 5 are now factors of 15.
Therefore, 15 is divisible by both:
3X + 5Y = 15,
Let X = 0,
3*0 + 5Y = 15,
5Y = 15,
Y = 3 = YInt.
Let Y = 0,
3X + 5*0 = 15,
3X = 15,
X = 5 = XInt.
Graph: (0 , 3) , (5 , 0). 
8th grade  Cassie, Thursday, September 19, 2013 at 5:00pm
15!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!LOL IDK

8th grade  Nandhika Sivakumar, Thursday, September 3, 2015 at 2:18pm
It is 15=k math is fun and awesome!!!

8th grade  Sandy, Thursday, September 3, 2015 at 2:28pm
15 is the answer and I have a question "if a is not equal to 0, find the intercepts of the graph of y=ax+b in terms of a and b?"