Posted by **Monkeylover:)** on Thursday, November 4, 2010 at 7:33pm.

Consider the equation 3x+5y=k, what values could k so that the x-intercept and y- intercept on teh equations graph would both be integers. explain.

- 8th grade -
**SraJMcGin**, Friday, November 5, 2010 at 3:04am
If this is algebra, for example, please label the School Subject correctly. Otherwise the correct teacher may never read your post.

Sra

- 8th grade -
**Henry**, Friday, November 5, 2010 at 11:57pm
3X + 5Y = K.

k = A * B = 3 * 5 = 15.

3 and 5 are now factors of 15.

Therefore, 15 is divisible by both:

3X + 5Y = 15,

Let X = 0,

3*0 + 5Y = 15,

5Y = 15,

Y = 3 = Y-Int.

Let Y = 0,

3X + 5*0 = 15,

3X = 15,

X = 5 = X-Int.

Graph: (0 , 3) , (5 , 0).

- 8th grade -
**Cassie**, Thursday, September 19, 2013 at 5:00pm
15!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!LOL IDK

- 8th grade -
**Nandhika Sivakumar**, Thursday, September 3, 2015 at 2:18pm
It is 15=k math is fun and awesome!!!

- 8th grade -
**Sandy**, Thursday, September 3, 2015 at 2:28pm
15 is the answer and I have a question "if a is not equal to 0, find the intercepts of the graph of y=ax+b in terms of a and b?"

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