8th grade
posted by Monkeylover:) on .
Consider the equation 3x+5y=k, what values could k so that the xintercept and y intercept on the equations graph would both be integers. explain.

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Sra 
3X + 5Y = K.
k = A * B = 3 * 5 = 15.
3 and 5 are now factors of 15.
Therefore, 15 is divisible by both:
3X + 5Y = 15,
Let X = 0,
3*0 + 5Y = 15,
5Y = 15,
Y = 3 = YInt.
Let Y = 0,
3X + 5*0 = 15,
3X = 15,
X = 5 = XInt.
Graph: (0 , 3) , (5 , 0). 
15!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!LOL IDK

It is 15=k math is fun and awesome!!!

15 is the answer and I have a question "if a is not equal to 0, find the intercepts of the graph of y=ax+b in terms of a and b?"