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Posted by on Thursday, November 4, 2010 at 7:01pm.

How many total Roots are in this polynomial equation?

(x-4)^5(x^2-11)(x^2+49)=0

  • Algebra - , Friday, November 5, 2010 at 11:16am

    (x-4)^5(x^2-11)(x^2+49)=0
    (x-4)^5*(x^4-11x^2+49x^2-539)
    =(x-4)^5*(x^4+38x^2-539)

    (x-4)^5* 5 degre

    (x^4+38x^2-539) 4 degre

    5+4=9
    Polynome have 9 degres and have 9 roots.

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