Posted by Asheley on Thursday, November 4, 2010 at 7:01pm.
How many total Roots are in this polynomial equation?
(x4)^5(x^211)(x^2+49)=0

Algebra  Bosnian, Friday, November 5, 2010 at 11:16am
(x4)^5(x^211)(x^2+49)=0
(x4)^5*(x^411x^2+49x^2539)
=(x4)^5*(x^4+38x^2539)
(x4)^5* 5 degre
(x^4+38x^2539) 4 degre
5+4=9
Polynome have 9 degres and have 9 roots.