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March 3, 2015

March 3, 2015

Posted by **Asheley** on Thursday, November 4, 2010 at 7:01pm.

(x-4)^5(x^2-11)(x^2+49)=0

- Algebra -
**Bosnian**, Friday, November 5, 2010 at 11:16am(x-4)^5(x^2-11)(x^2+49)=0

(x-4)^5*(x^4-11x^2+49x^2-539)

=(x-4)^5*(x^4+38x^2-539)

(x-4)^5* 5 degre

(x^4+38x^2-539) 4 degre

5+4=9

Polynome have 9 degres and have 9 roots.

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