Posted by **Gage** on Thursday, November 4, 2010 at 5:29pm.

I THINK SOMEONE HAS THIS SAME QUETION! A massless spring of constant k = 91.0 N/m is fixed on the left side of a level track. A block of mass m = 0.50 kg is pressed against the spring and compresses it a distance of d. The block (initially at rest) is then released and travels toward a circular loop-the-loop of radius R = 1.5 m. The entire track and the loop-the-loop are frictionless, except for the section of track between points A and B. Given that the coefficient of kinetic friction between the block and the track along AB is ľk = 0.24, and that the length of AB is 2.5 m, determine the minimum compression d of the spring that enables the block to just make it through the loop-the-loop at point C. [Hint: The force of the track on the block will be zero if the block barely makes it through the-loop-the-loop.]

- Physics -
**bobpursley**, Thursday, November 4, 2010 at 5:49pm
Assuming point C is at the top, then

g= v^2/r so you have to calculate v at the top.

So energy at the bottom must equal KE at the top + the change in PE to get to the top

RequiredKEbotom= 1/2 m*vtop^2+mg(2r)

Now, you have losses before you get there due to friction, mu*mg*2.5, so that has to be added to get the initial KE at the spring.

PEspring= mu*mg*2.5+1/2m vtop^2+mg(2r)

PE spring= 1/2 k d^2, solve for d.

- Physics -
**Gage**, Thursday, November 4, 2010 at 6:21pm
thank you, but i am exteremly confused! so i just use PE spring to find d?

- Physics -
**Gage**, Thursday, November 4, 2010 at 6:39pm
i guess i'm just confused on the mu means static friction? .24?

- Physics -
**Gage**, Thursday, November 4, 2010 at 6:41pm
is mu friction? .24?

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