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When heated, N2O4 dissociates as follows: N2O4 =2NO2
A flask initially contians .560 M N2O4. at this temperature, Kc is 4.00. what is the equilibrium concentration of NO2?

  • Chemistry - ,

    Set up an ICE chart, substitute into Kc, and solve.
    N2O4 = .560 M
    NO2 = 0

    NO2 = +2x
    N2O4 = -x

    N2O4 = 0.560-x
    NO2 = 2x

    Solve for x, then 2x will be (NO2). Post your work if you get stuck.

  • Chemistry - ,

    i ended up with x=.28 and i multiplied it by 2 and it was not the right answer

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