Posted by Hannah on Thursday, November 4, 2010 at 3:24pm.
consider it as
y = 5/(x+3)
Can you replace any number for y ?
let's try y = 8
8 = 5/(x+3)
8x + 24 = 5
etc.
notice we could put any number for y and we would get a solution for x, or ....
what about y = 0
0 = 5/(x+3)
0(x+3) = 5
0 = 5 -----> contradiction
so y can be anything except y ≠ 0
there is your range.
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