Posted by **Hannah** on Thursday, November 4, 2010 at 3:24pm.

The following function f is one-to-one; find its domain and range.

f(x) = 5 / x+3

Domain = x cannot be -3

Range= I do not know how to find this.

- Math -
**Reiny**, Thursday, November 4, 2010 at 4:43pm
consider it as

y = 5/(x+3)

Can you replace any number for y ?

let's try y = 8

8 = 5/(x+3)

8x + 24 = 5

etc.

notice we could put any number for y and we would get a solution for x, or ....

what about y = 0

0 = 5/(x+3)

0(x+3) = 5

0 = 5 -----> contradiction

so y can be anything except y ≠ 0

there is your range.

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