Homework Help: Chemistry

Posted by Lisa on Thursday, November 4, 2010 at 2:58pm.

How much heat, in kilojoules, is associated with the production of 273kg of slaked lime, Ca(OH)2?

CaO(s)+H2O(l)-->Ca(OH)2(s)
delta H=-65.2kJ

Chemistry - DrBob222, Thursday, November 4, 2010 at 3:06pm
So you get 65.2 kJ heat from 1 mole (74.09 g) Ca(OH)2.
-65.2 kJ x (273/74.09) = ??
Chemistry - WhatHeSaid, Monday, February 7, 2011 at 1:30am
What he said, except you actually multiply by positive 65.2kJ.
Chemistry - Chillymcfreeze, Wednesday, October 31, 2012 at 1:08am
In order to solve this, you need to relate the ratio of kJ of heat and the moles of Ca(OH)2 in the reaction, to an unknown kJ of heat and moles of Ca(OH)2 in 273kg. 1 mole of Ca(OH)2 = 74.09g
Set up a proportion:

65.2kJ/74.09g = ??kJ/273000g

Then cross multiply the 65.2 and the 273000, and divide by the 74.09

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