Saturday

December 20, 2014

December 20, 2014

Posted by **Ashley** on Thursday, November 4, 2010 at 2:03pm.

- logarithmic differentiation -
**Reiny**, Thursday, November 4, 2010 at 2:33pmfirst take ln of both sides

ln y = ln(x^-cosx)

ln y = -cosx lnx

now differentiate with respect to x

(dy/dx)/y = -cosx (1/x) + lnx (sinx)

dy/dx = y ( -(1/x)cosx + lnx(sinx))

= x^-cosx ( -(1/x)cosx + lnx(sinx))

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