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March 28, 2017

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What is the molarity of OH- in a 7.68×10-4 M NaClO solution that hydrolyzes according to the equation.

ClO-(aq) + H2O(l) = OH-(aq) + HClO(aq)

Constants: Kh=2.86×10-7

Can someone help me figure this one out?

  • chemistry - ,

    Kh = (OH^-)(HClO)/(ClO^-).
    Let x = (HClO), then x = (OH^-)
    and (ClO^-) = 7.68 x 10^-4 -x
    Solve for x.

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