Posted by sparkle on .
The base dissociation equilibrium constant (Kb) for C5H5N is 1.40×10-9 (eq. 1).
(eq. 1): C5H5N(aq) + H2O(l) = OH-(aq) + C5H5NH+(aq)
Calculate the value of the equilibrium constant (Ka) for the hydrolysis of C5H5NH+ as shown in the reaction (eq. 2).
(eq. 2): C5H5NH+(aq) + H2O(l) = H3O+(aq) + C5H5N(aq)
sorry for so many questions
college chemistry -
Ka = (Kw/Kb).
Just remember that KaKb = Kw. The Ka and Kb are interchangeable with that formula.