An object is moving to the right at a speed of 4 m/s. Four forces(10N North, 10N South, 20N Left, 20N Right) are applied to the object at the same time. What will be the object's speed in m/s after the forces are applied?
The object has not net force, therefore, no net acceleration. It has constant velocity.
thank you. so the speed will stay at 4 m/s?
To find the object's speed after the forces are applied, we need to consider the net force acting on the object. This can be found by summing up the forces in each direction.
First, let's break down the forces in the x and y directions:
- In the y-direction, we have two opposing forces: 10N to the North and 10N to the South. Since these forces are equal and opposite, they cancel each other out. Therefore, the net force in the y-direction is zero.
- In the x-direction, we have two opposing forces as well: 20N to the Left and 20N to the Right. Similarly, these forces cancel each other out, resulting in a net force of zero in the x-direction.
Since the net force is zero in both the x and y directions, the object's speed will remain unaffected after the forces are applied. Therefore, the object's speed remains at 4 m/s.