Balance the equation in aqueous basic solution:

Fe(CN)64-(aq) + Ce4+(aq) → Ce3+(aq) + Fe3+(aq) + CO32-(aq) + NO3-(aq)

Again you need to check you have the correct equation as you have O atoms on the RHS but none on the LHS.

To balance the given equation in aqueous basic solution, which contains OH- ions, you need to follow these steps:

Step 1: Write the unbalanced equation.
Fe(CN)64-(aq) + Ce4+(aq) → Ce3+(aq) + Fe3+(aq) + CO32-(aq) + NO3-(aq)

Step 2: Balance the elements other than hydrogen and oxygen.
Let's start by balancing the atoms that are not hydrogen (H) and oxygen (O). In this equation, we can begin with the iron (Fe) atoms since there is only one Fe atom on each side:

Fe(CN)64-(aq) + Ce4+(aq) → Ce3+(aq) + Fe3+(aq) + CO32-(aq) + NO3-(aq)
Fe(CN)64-(aq) + Ce4+(aq) → Ce3+(aq) + Fe3+(aq) + CO32-(aq) + NO3-(aq)
____
Now the Fe atoms are balanced.

Step 3: Balance the hydrogen (H) atoms using water (H2O).
Next, let's balance the hydrogen atoms. In this equation, the H atoms only appear in the hydroxide ion (OH-) on the right side. Therefore, we will add water (H2O) molecules to the left side to balance the hydrogen:

Fe(CN)64-(aq) + Ce4+(aq) + H2O(l) → Ce3+(aq) + Fe3+(aq) + CO32-(aq) + NO3-(aq)
Fe(CN)64-(aq) + Ce4+(aq) + H2O(l) → Ce3+(aq) + Fe3+(aq) + CO32-(aq) + NO3-(aq)
____
Now the hydrogen atoms are balanced.

Step 4: Balance the oxygen (O) atoms using hydroxide ions (OH-).
Lastly, let's balance the oxygen atoms. In this equation, the oxygen atoms appear in various ions, including OH-, CO32-, and NO3-. To balance the oxygen, we'll add hydroxide ions (OH-) to the left side since they only contain oxygen:

Fe(CN)64-(aq) + Ce4+(aq) + H2O(l) + OH-(aq) → Ce3+(aq) + Fe3+(aq) + CO32-(aq) + NO3-(aq)
Fe(CN)64-(aq) + Ce4+(aq) + H2O(l) + OH-(aq) → Ce3+(aq) + Fe3+(aq) + CO32-(aq) + NO3-(aq)
____
Now the equation is balanced.

Step 5: Check the charge balance.
In the final step, it's important to verify that the charges on both sides of the equation are balanced. In this equation, the total charge on each side is the same (both zero), so we don't need to make any additional modifications.

The balanced equation in aqueous basic solution is:
Fe(CN)64-(aq) + Ce4+(aq) + H2O(l) + OH-(aq) → Ce3+(aq) + Fe3+(aq) + CO32-(aq) + NO3-(aq)