how many moles of butane gas c4h10 react to produce 3.50moles of water?

I believe you would get the molar mass of C4H10 and also the molar mass of water (H20). So C4H10 gives us a molar mass of 58.14 grams/mol and water gives us a molar mass of 18.02 grams/mol. You then would set it up 58.14 grams x mol/ 18.02 grams. Grams cancel and leave you with moles.

58.14g x mol = ?
18.02 g

2C4H10 + 13O2 ==> 8CO2 + 10H2O

Use the coefficients in the balanced equation to convert from moles of one thing to moles of any other in the same equation.
moles butane = 3.5 moles H2O x (2 moles butane/10 moles H2O) = 3.5*(2/10) = ??

To determine the number of moles of butane gas (C4H10) that react to produce 3.50 moles of water (H2O), you need to first balance the chemical equation for the reaction.

The balanced equation for the reaction between butane and water is:

C4H10 + O2 → CO2 + H2O

From the balanced equation, we can see that for every mole of butane (C4H10) that reacts, an equal number of moles of water (H2O) is produced. Therefore, the mole ratio between butane and water is 1:1.

Since 1 mole of butane reacts to produce 1 mole of water, the number of moles of butane gas required to produce 3.50 moles of water is also 3.50 moles.

So, 3.50 moles of butane gas (C4H10) would react to produce 3.50 moles of water (H2O).

oops, disregard the last part it didn't line up right. It will just be 58.14/ 18.02 which gives you moles