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April 18, 2014

April 18, 2014

Posted by **Rac** on Thursday, November 4, 2010 at 1:14am.

- geometry -
**Henry**, Friday, November 5, 2010 at 6:11pmI drew the vector for ship # 1 @ 0 deg

and ship # 2 @ 140 deg.

d1 = 26 mi / h * 3 h = 78 mi @ 0 deg.

d2 = 34 mi / h * 3 h = 102 mi @ 140 deg.

d = 102 mi @ 140 deg - 78 mi @ 0 deg.

X = hor = 102 * cos140 - 78cos0,

= -78.1 - 78 = - 156.1 mi.

Y = ver = 102sin140 - 78sin0

= 65.6 - 0 = 65.6 mi.

d^2 = x^2 + y^2,

= 24367.2 + 4298.7,

= 28665.9,

d = sqrt(28665.9) = 169.3 miles apart.

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