Friday
November 28, 2014

Homework Help: Chemistry

Posted by Tokey on Thursday, November 4, 2010 at 12:40am.

Organic chemistry:

an attempt at synthesizing a certain optically active compound resulted in a mixture of its enantiomers. The mixture had an observed specific rotation of 11.0 degrees. If it is known that the specific rotation of the R enantiomer is -33.6 degrees, determine the percent of each enantiomer in the mixture.

So i have the equation set up:

11= x(-33.6) +(1-x)(spec. rot of S)
but how do i solve for x when the specific rotation of S is unknown?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Chemistry - If the specific rotation of Compound X is (-) 123.8, what would be ...
Chemistry(the) - An optically active compound having molecular formula C6H12O6 ...
Organic Chemistry - How can I tell if a structure of a compound will be ...
Organic Chemistry - A 0.160 M solution of an enantiomerically pure chiral ...
Chemistry - In a certain mixture, one compound may be decomposed by heating, ...
Chemistry(Please help) - I know that to calculate the specific rotation for a ...
Chemistry - Suppose you had a mixture consisting of 20.0 g of compound A and 20....
Chemistry - An unknown compound X is one of the four compounds listed in the ...
Organic Chemistry - how to calculate specific observed rotation?
Organic Chemistry - Is ethyl cyclohexane optically active?

Search
Members