Posted by Adam on Thursday, November 4, 2010 at 12:19am.
take log on both sides, and differentiate. Solve for y'.
y=9sin(x)^x
ln(y)=ln(9)+x*ln(sin(x))
differentiate:
(1/y)y' = ln(sin(x))+(x/sin(x))*cos(x)
y'=y(ln(sin(x))+(x/sin(x))*cos(x))
=9sin(x)^x * (ln(sin(x))+(x/sin(x))*cos(x))
Simplify the answer and check.
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