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April 24, 2014

April 24, 2014

Posted by **NEED HELP!!!!** on Wednesday, November 3, 2010 at 11:14pm.

f(x)=sin(x/4)^2

defined on the interval [-12.266371, 2.241593].

Rememer that you can enter pi for as part of your answer.

a.)f(x) is concave down on the interval ____.

b.) A global minimum for this function occurs at ____.

c.) A local maximum for this function which is not a global

maximum occurs at _____.

d.) The function is increasing on the region _____.

- Math: Calculus -
**NEED HELP!!!!**, Thursday, November 4, 2010 at 12:28amI REALLY NEED HELP ANSWERING THIS. I mange to get b and c but i'm stuck on the other two

- Math: Calculus -
**MathMate**, Thursday, November 4, 2010 at 8:11amWhat did you get for b & c?

For concavity and increasing, you need to calculate f"(x) within the interval.

Concavity changes when f"(x)=0. f"(x)>0 is concave upwards, and vice versa.

Function's and increasing/decreasing changes only when f'(x)=0. When f'(x)>0 it is increasing, and vice versa.

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