how do i work out the equation

S= B + 1/2Pl solving for l

s=b+(1/2p)(l)

Step 1: Flip the equation.
1/2lp+b=s
Step 2: Add -b to both sides.
1/2lp+b+−b=s+−b
1/2lp=−b+s
Step 3: Divide both sides by p/2.
1/2lp = −b+s
p/2 p/2
l=−2b+2s / p
Answer:
l=−2b+2s / p

To solve for "l" in the equation S = B + 1/2Pl, you can follow these steps:

1. Start by isolating the term containing "l" on one side of the equation. In this case, we need to isolate the term 1/2Pl.

Subtract B from both sides of the equation:
S - B = 1/2Pl

2. Now, we want to get rid of the coefficient of "l", which is the value 1/2P. To do so, we'll multiply both sides of the equation by the reciprocal of 1/2P. The reciprocal of 1/2P is 2P/1 or simply 2P.

Multiply both sides of the equation by 2P:
(S - B) * 2P = (1/2Pl) * 2P

Simplify the right side:
2P * (S - B) = l

3. Finally, simplify the equation further to obtain the solution for "l" by multiplying the terms inside the parentheses.

Distribute the 2P to (S - B):
2PS - 2PB = l

Therefore, the equation S = B + 1/2Pl can be rearranged to solve for "l" as:
l = 2PS - 2PB

I don't see I. I see a S, and a B. 1/2 PI is a constant.