Please help me solve this..
It costs $10 plus $8 per hour to rent a canoe. Brandon and Erin have $50. Solve the following equation to find how many hours they can rent a canoe.
8h +10 = 50
8h +10 = 50
8h + 10 - 10 = 50 - 10
8h = 40
8h/8 = 40/8
h = 5
thank you Ms. Sue
To solve the equation 8h + 10 = 50, we need to isolate the variable h (representing the number of hours they can rent a canoe).
Step 1: Start with the given equation.
8h + 10 = 50
Step 2: Subtract 10 from both sides of the equation to isolate the term containing h.
8h + 10 - 10 = 50 - 10
8h = 40
Step 3: Divide both sides of the equation by 8 to solve for h.
8h/8 = 40/8
h = 5
Therefore, they can rent a canoe for 5 hours.
To solve the equation 8h + 10 = 50, we need to isolate the variable h (which represents the number of hours they can rent a canoe) on one side of the equation.
Step 1:
Start by subtracting 10 from both sides of the equation:
8h + 10 - 10 = 50 - 10
This simplifies to:
8h = 40
Step 2:
Next, to isolate the variable h, divide both sides of the equation by 8:
8h / 8 = 40 / 8
This simplifies to:
h = 5
Therefore, they can rent a canoe for 5 hours with their $50.