What is the molarity of a bleach solution containing 8.9 g of NaOCl per liter of bleach?
moles = grams/molar mass
solve for moles.
Then M = moles/L
To find the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters).
The first step is to calculate the moles of NaOCl in the solution. The molar mass of NaOCl is the sum of the atomic masses of its constituent elements: Na (sodium) has a molar mass of 22.99 g/mol, O (oxygen) has a molar mass of 16.00 g/mol, and Cl (chlorine) has a molar mass of 35.45 g/mol. Adding these up, we get:
Molar mass of NaOCl = 22.99 g/mol + 16.00 g/mol + 35.45 g/mol = 74.44 g/mol.
Given that there are 8.9 grams of NaOCl in 1 liter of bleach solution, we can now calculate the moles of NaOCl:
Moles of NaOCl = mass / molar mass = 8.9 g / 74.44 g/mol.
Now that we have the moles of NaOCl, we need to find the volume of the solution in liters. We are told that the solution has a volume of 1 liter.
Finally, we can calculate the molarity (M) of the bleach solution using the formula:
Molarity = moles of solute / volume of solution.
Substituting the values we calculated:
Molarity = (8.9 g / 74.44 g/mol) / 1 L.
This simplifies to:
Molarity = 0.1195 mol / L.
Therefore, the molarity of the bleach solution is approximately 0.1195 M.