A baseball is hit at ground level. The ball reaches its maximum height above ground level 2.6 s after being hit. Then 2.1 s after reaching its maximum height, the ball barely clears a fence that is 96.4 m from where it was hit. Assume the ground is level.
(a) What maximum height above ground level is reached by the ball?
(b) How high is the fence?
(c) How far beyond the fence does the ball strike the ground?
physics - bobpursley, Wednesday, November 3, 2010 at 5:41pm
one last equation: at max height, vy=0
Lets see. Solve the third equation for VisinTheta, put that into the second equation, solve for h (answer b)
then max height:
solve for hmax using the same expression you had in equation 3.