Posted by **tom** on Wednesday, November 3, 2010 at 5:03pm.

A baseball is hit at ground level. The ball reaches its maximum height above ground level 2.6 s after being hit. Then 2.1 s after reaching its maximum height, the ball barely clears a fence that is 96.4 m from where it was hit. Assume the ground is level.

(a) What maximum height above ground level is reached by the ball?

m

(b) How high is the fence?

m

(c) How far beyond the fence does the ball strike the ground?

m

- physics -
**bobpursley**, Wednesday, November 3, 2010 at 5:41pm
Horizontal equation:

96.4=VicosTheta*4.7

Vertical equation:

h=ViSinTheta*4.7-4.9(4.7^2)

one last equation: at max height, vy=0

0=ViSinTheta*2.6-4.9(2.6^2)

Lets see. Solve the third equation for VisinTheta, put that into the second equation, solve for h (answer b)

then max height:

hmax=visintheta(2.6)-4.9(2.6^2)

solve for hmax using the same expression you had in equation 3.

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