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Posted by on Wednesday, November 3, 2010 at 5:03pm.

A baseball is hit at ground level. The ball reaches its maximum height above ground level 2.6 s after being hit. Then 2.1 s after reaching its maximum height, the ball barely clears a fence that is 96.4 m from where it was hit. Assume the ground is level.
(a) What maximum height above ground level is reached by the ball?
m
(b) How high is the fence?
m
(c) How far beyond the fence does the ball strike the ground?
m

  • physics - , Wednesday, November 3, 2010 at 5:41pm

    Horizontal equation:

    96.4=VicosTheta*4.7
    Vertical equation:
    h=ViSinTheta*4.7-4.9(4.7^2)
    one last equation: at max height, vy=0
    0=ViSinTheta*2.6-4.9(2.6^2)

    Lets see. Solve the third equation for VisinTheta, put that into the second equation, solve for h (answer b)

    then max height:
    hmax=visintheta(2.6)-4.9(2.6^2)
    solve for hmax using the same expression you had in equation 3.

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