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November 28, 2014

November 28, 2014

Posted by **REALLY NEED HELP!!!!** on Wednesday, November 3, 2010 at 12:03am.

f(x) = \frac{ x^3 }{ x^2 - 36 }

defined on the interval [ -20, 16 ].

A. The function f(x) has vertical asympototes at____ and___

B. f(x) is concave up on the region___ to and____ to___

C. The inflection point for this function is when x = ____

- Math: Calculus -
**REALLY NEED HELP!!!!**, Wednesday, November 3, 2010 at 12:04amf(x)=(x^3)/(x^2-36)

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