Saturday

January 31, 2015

January 31, 2015

Posted by **REALLY NEED HELP!!!!** on Wednesday, November 3, 2010 at 12:03am.

f(x) = \frac{ x^3 }{ x^2 - 36 }

defined on the interval [ -20, 16 ].

A. The function f(x) has vertical asympototes at____ and___

B. f(x) is concave up on the region___ to and____ to___

C. The inflection point for this function is when x = ____

- Math: Calculus -
**REALLY NEED HELP!!!!**, Wednesday, November 3, 2010 at 12:04amf(x)=(x^3)/(x^2-36)

**Answer this Question**

**Related Questions**

Calculus - Answer the following questions for the function f(x) = sin^2(x/3) ...

Math: Calculus - Answer the following questions for the function f(x)=sin(x/4)^...

Calculus - Answer the following questions for the function f(x) = sin^2(x/3) ...

Calculus - Answer the following questions for the function f(x) = sin^2(x/3) ...

math - Answer the following questions for the function f(x)=sin^2(x/5) defined ...

math - Answer the following questions for the function f(x)=x(sqrtx2+25) defined...

Calculus - Answer the following questions for the function f(x)=(x^3-9x^2+27x-27...

Calculus - f(x) = sin^2(x/2) defined on the interval [ -5.683185, 1.270796]. ...

CALCULUs - For all x in the interval [-11,13] the function f is defined by x^3(x...

Calculus please help me - f(x) = \frac{ x^3 }{ x^2 - 25 } defined on the ...