pre cal
posted by Anonymous on .
find the exact value of tan(2sin1 3/5)

let sin^1 (3/5) = Ø
then sinØ = 3/5 and cosØ = 4/5
so you want tan 2Ø
= sin2Ø/cos2Ø
= 2sinØcosØ/(2cos^2Ø  1)
= 2(3/5)(4/5)/(32/25  1)
=(24/25) / (7/25)
= (24/25)(25/7)
= 24/7