Posted by bobjahng on Tuesday, November 2, 2010 at 7:33pm.
a) ball relativeground=Juansspeed+ball relative to Juan
13.6Cos32.5N + 13.6Sin32.5E =7.8N+ballrelative to Juan
ball relative to Juan= (13.6Cos32.5-7.8)N+13.6Sin32.5E
so figure out the N component, then magnitude= sqrt (Ncomp^2+Ecomp^2)
i got the right answer for part a (8.18)
now how do i do part b?
you have the vector:
Ncomp, E component
relative to Juan, going N, so it is E of him by theta, where tantheta=Ecomp/Ncomp
i cant get part b!!!!!!! im completely lost >.<
Hi Chris
On that Kobe System.
Or Linsanity
Make sure you're putting the parenthesis in the correct place. Such as for part A, the formulas should be:
a) (ball relative ground) = (Juan's speed)+ (ball relative to Juan)
(13.6Cos(32.5))N + (13.6Sin(32.5))E =(7.8)N+(ball relative to Juan)
ball relative to Juan= (13.6(Cos(32.5))-7.8)N+(13.6Sin(32.5))E
so figure out the N component, then magnitude= sqrt (Ncomp^2+Ecomp^2)
Related Questions
Physics - In a World Cup soccer match, Juan is running due north toward the goal...
Physics - An airplane flies due north at 160 km/h with respect to the air. There...
Physics - An airplane flies due north at 250 km/h relative to the air. There is ...
Physics - You are in a hot-air balloon that, relative to the ground, has a ...
Physics - An airplane flies due north at 145 km/h with respect to the air. There...
physics - An airplane has a velocity relative to the air of 192 m/s in the ...
physics - An airplane has a velocity relative to the air of 181 m/s in a ...
physic - An airplane flies due north at 200 km/h relative to the air. There is a...
science - An airplane flies due north at 235 km/h relative to the air. There is ...
physics 111 - A runner times his speed around a circular track with a ...
For Further Reading