Posted by bobjahng on Tuesday, November 2, 2010 at 7:33pm.
In a World Cup soccer match, Juan is running due north toward the goal with a speed of 7.80 m/s relative to the ground. A teammate passes the ball to him. The ball has a speed of 13.6 m/s and is moving in a direction of 32.5 degrees east of north, relative to the ground.
a)What is the magnitude of the ball's velocity relative to Juan?
b)What is the direction of the ball's velocity relative to Juan?
How do you start this off? I found the y component and subtracted it to find the answer for the first part, but it says that my answer is wrong.

physics  bobpursley, Tuesday, November 2, 2010 at 7:43pm
a) ball relativeground=Juansspeed+ball relative to Juan
13.6Cos32.5N + 13.6Sin32.5E =7.8N+ballrelative to Juan
ball relative to Juan= (13.6Cos32.57.8)N+13.6Sin32.5E
so figure out the N component, then magnitude= sqrt (Ncomp^2+Ecomp^2)

physics  bobjahng, Tuesday, November 2, 2010 at 7:55pm
i got the right answer for part a (8.18)
now how do i do part b?

physics  bobpursley, Tuesday, November 2, 2010 at 8:27pm
you have the vector:
Ncomp, E component
relative to Juan, going N, so it is E of him by theta, where tantheta=Ecomp/Ncomp

physics  billy, Wednesday, November 3, 2010 at 3:13pm
i cant get part b!!!!!!! im completely lost >.<

physics  Juan, Friday, February 17, 2012 at 4:14am
Hi Chris

physics  El Piton, Friday, February 17, 2012 at 4:15am
On that Kobe System.
Or Linsanity

physics  Annie, Tuesday, September 25, 2012 at 8:46pm
Make sure you're putting the parenthesis in the correct place. Such as for part A, the formulas should be:
a) (ball relative ground) = (Juan's speed)+ (ball relative to Juan)
(13.6Cos(32.5))N + (13.6Sin(32.5))E =(7.8)N+(ball relative to Juan)
ball relative to Juan= (13.6(Cos(32.5))7.8)N+(13.6Sin(32.5))E
so figure out the N component, then magnitude= sqrt (Ncomp^2+Ecomp^2)
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