# Physics

posted by
**Dee** on
.

What is the pressure difference required to make blood flow through artery of inner radius 2.0 mm and length 0.18 m at a speed of 5.6 cm/s?

I used P1-P2 = speed*8*n*L/r squared

n = viscosity of blood = 4 x 10e-3

L = .18 m

r = 2 x 10e-3 m

When plugged in I get P1-P2 - 80.64 Pa but this is wrong! Help!