An open pipe 0.40m in length is placed vertically in a cylindrical bucket having a bottom area of 0.10 m^2. Water is poured into the bucket until a sounding tuning fork of frequency 440 Hz, placed over the pipe, produces resonance. Find the mass of water in the bucket at this moment.
I've been totally stumped in this, all I got was a very brief overview of standing waves in open and closed air columns. Totally lost.
11th grade Physics - bobpursley, Tuesday, November 2, 2010 at 3:26pm
The closed pipe is 1/4 lambda long (closed at the bottom due to water).
so the height of the water is .4-1/4 lambda
volume water= area*heighwater
mass water=denstiy water*volume water