If 36.00 mL of KMnO4 solution are required to oxidize 25.00mL of 0.02932 M Na2C2O4 solution what is the concentration of KMnO4?
You must write a balanced redox equation.
moles KMnO4 = M x L
Using the coefficients in the balanced equation, convert moles KMnO4 to mole Na2C2O4. Then
M C2O4 = moles/L
To find the concentration of KMnO4 solution, we need to use the concept of stoichiometry and the given information about the volume and concentration of Na2C2O4 solution.
First, let's write the balanced chemical equation for the reaction:
2 KMnO4 + 5 Na2C2O4 + 8 H2SO4 -> 2 MnSO4 + 10 CO2 + 8 H2O + 5 Na2SO4 + K2SO4
From the balanced equation, we can see that the mole ratio between KMnO4 and Na2C2O4 is 2:5 (the coefficients in front of the compounds).
Given:
Volume of KMnO4 solution (V1) = 36.00 mL
Volume of Na2C2O4 solution (V2) = 25.00 mL
Concentration of Na2C2O4 solution (C2) = 0.02932 M
Step 1: Convert volumes to liters
V1 = 36.00 mL = 0.03600 L
V2 = 25.00 mL = 0.02500 L
Step 2: Calculate the number of moles of Na2C2O4 using the formula:
moles = concentration × volume
moles of Na2C2O4 (n2) = C2 × V2
n2 = 0.02932 M × 0.02500 L
Step 3: Use the mole ratio to calculate the number of moles of KMnO4 (n1).
From the balanced equation, we know that the mole ratio of KMnO4 to Na2C2O4 is 2:5.
n1/n2 = 2/5
n1 = (2/5) × n2
Step 4: Calculate the concentration of KMnO4 (C1) using the formula:
C1 = n1/V1
C1 = [(2/5) × n2] / 0.03600 L
Plug in the value of n2 from Step 2 to get the final answer.
By following these steps and plugging in the given values, you can find the concentration of KMnO4.