Posted by **priya ** on Tuesday, November 2, 2010 at 1:29am.

I need help with this question

determine the values in k for which the function f(x)= 4x^2-3x+2kx+1 has two zeros. Check these values in the original equation.

i don't get how to do it please help me.

- math grade 11 -
**Henry**, Thursday, November 4, 2010 at 7:45pm
F(x) = Y = 4x^2 - 3x + 2kx + 1.

This problem was solved by using EXCEL spread sheets and trial & error.

First, I temporarily ignored the 3rd term (2kx); and I changed b (the coefficient of x) until I found the required zeroes. Then I calculated the corresponding value of k:

b = -3 + 2k = 5,

-3 + 2k = 5,

2k = 5 + 3,

2k = 8,

k = 8 / 2 = 4.

5 was chosen for b because it gave 2

zeroes.

So when k = 4: (-1 , 0) , (-1/4 , 0).

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