i need help setting it up to find the answers. (answers included)

two masses are connected together by a string which is then hung over a pulley. m1= 7.50 kg and m2= 6.50 kg. before they are released m1 is suspended h= 135cm above the floor while m2 is sitting on the floor.
a.what will be the resulting acceleration of this system (.71 m/s^2)
b. what will be the tension in the string as m1 accelerates to the floor? (69.7 N)
c. how long will it take for m1 to reach the floor? (1.95s)
d. what will be the velocity of m1 just as it reaches the floor? (1.38 m/s)

whats the angle?

To determine the answers, you need to apply the principles of Newton's second law and equations of motion. Here's a step-by-step explanation of how to find the answers:

a. First, calculate the net force acting on the system:
- The weight of m1 is given by: W1 = m1 * g, where g is the acceleration due to gravity (approximately 9.8 m/s^2).
- The weight of m2 is given by: W2 = m2 * g.
- Since m1 is at a height above the floor, it has gravitational potential energy (PE1 = m1 * g * h).
- When the system is released, m1 will accelerate downward while m2 will experience an upward force due to the tension in the string.
- The net force can be expressed as: Fnet = (m1 * g) - (m2 * g) = (m1 - m2) * g.
- Acceleration (a) can be calculated using Newton's second law: Fnet = m1 * a, so a = Fnet / m1.

b. To find the tension in the string as m1 accelerates to the floor, consider the forces acting on m1:
- The downward force due to gravity is balanced by the tension in the string.
- The tension (T) in the string can be expressed as: T = m1 * g - m1 * a.

c. Next, determine the time it takes for m1 to reach the floor:
- We know the acceleration (a) and the initial position (h).
- The equation for displacement (s) can be used: s = ut + (1/2) * a * t^2, where u is the initial velocity (0 in this case).
- Since m1 is initially at rest, s (displacement) will be equal to the height (h).
- The equation can be rewritten as: h = (1/2) * a * t^2.
- Rearrange the equation to solve for time (t): t = sqrt((2 * h) / a).

d. Finally, to find the velocity of m1 just as it reaches the floor:
- Use the equation of motion relating displacement, final velocity (v), initial velocity (u), and acceleration (a): v^2 = u^2 + 2as.
- Since m1 is initially at rest, the initial velocity (u) is 0.
- The displacement (s) is the same as the height (h).
- Rearrange the equation to solve for final velocity (v): v = sqrt(2 * a * h).

Now, substitute the given values for m1, m2, h, and g into the above equations to calculate the answers.

a. The resulting acceleration of the system is approximately 0.71 m/s^2, calculated using the equation a = Fnet / m1.
b. The tension in the string as m1 accelerates to the floor is approximately 69.7 N, calculated using the equation T = m1 * g - m1 * a.
c. It will take approximately 1.95 seconds for m1 to reach the floor, calculated using the equation t = sqrt((2 * h) / a).
d. The velocity of m1 just as it reaches the floor is approximately 1.38 m/s, calculated using the equation v = sqrt(2 * a * h).