chemistry
posted by Bob on .
Two gases are contained in gas bulbs connected by a valve. Gas A is present in a 56 L bulb at a pressure of 213 torr. Gas B exerts a pressure of 683 torr in a 74 L bulb. What is the partial pressure of gas B after they
equilibrate once the valve has been opened? Answer in units of torr.

How many moles are in gas A?
Use PV = nRT and solve for n.
How many moles are in gas B?
Solve for n for that gas.
Now, using PV = nRT and a NEW volume (the final volume = 74L+56L = ??L) calculate the P of each gas by itself.
There is a much easier way to do it.
P1V1 = P2V2 for each gas. 
Thanks, I thought I could use Boyle's Law, but it seemed too easy.

0. 632atm