Posted by REALLY NEED HELP!!! on Monday, November 1, 2010 at 5:46pm.
My dimensions that I got is sqrt(215.625)*230/sqrt(215.625) but it's wrong.
cost = 5(2b+L) + 15 L = 10 b + 20 L
bL = 230 so b = 230/L
cost = 2300/L + 20 L
d cost/dL = -2300/L^2 + 20 L
= 0 for min
20 L = 2300/L^2
L ^3 = 115
L = 4.86
b = 47.3
check my arithmetic !!!
cost = 5(2b+L) + 15 L = 10 b + 20 L
bL = 230 so b = 230/L
cost = 2300/L + 20 L
d cost/dL = -2300/L^2 + 20 *******
= 0 for min
20 = 2300/L^2
L ^2 = 115
L = 10.72
b = 21.5
b = 47.3
cost=5*(2w+L)+15L
Area= Lw or w= ARea/L=230/L
cost= 10(230/L)+5L+15L
dcost/dL= -2300/L^2+20=0
L=sqrt 115 and w= 230/sqrt115
Related Questions
Calculus 1 - A fence is to be built to enclose a rectangular area of 220 square ...
calculus - A fence is to be built to enclose a rectangular area of 210 square ...
Calculus - A fence is to be built to enclose a rectangular area of 280 square ...
Math - A fence is to be built to enclose a rectangular area of 200 square feet. ...
PreCalculus - Three sides of a fence and an existing wall form a rectangular ...
Math - A farmer has 230 ft of fence to enclose a rectangular garden. What is the...
calculus - A rancher wants to fence in an area of 3000000 square feet in a ...
Math - A rectangular study area is to be enclosed by a fence and divided into ...
Calculus - A rancher wants to fence in an area of 500000 square feet in a ...
Calculus - A rancher wants to fence in an area of 5189400 square feet in a ...
For Further Reading